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8z^2-15z=0
a = 8; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·8·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*8}=\frac{0}{16} =0 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*8}=\frac{30}{16} =1+7/8 $
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